Skip to Main Content

CHE 105/110 Introduction to Chemistry - Exercises and Answers

Stoichiometry

Click here to return to Chapter 6

QUESTION ANSWER

1.

Think back to the pound cake recipe. What possible conversion factors can you construct relating the components of the recipe?

1.

1 pound butter 1 pound flour    or   1 pound sugar 1 pound eggs

are two conversion factors that can be constructed from the pound cake recipe. Other conversion factors are also possible.

3.

What are all the conversion factors that can be constructed from the balanced chemical reaction 2H2(g) + O2(g) → 2H2O(ℓ)?

 

3.

2 molecules H 2 1 molecule O 2 , 1 molecule O 2 2 molecules H 2 O , 2 molecules H 2 2 molecules H 2 O ,

and their reciprocals are the conversion factors that can be constructed.

5.

Given the chemical equation

Na(s) + H2O(ℓ) → NaOH(aq) + H2(g)
 
  1. Balance the equation.
  2. How many molecules of H2 are produced when 332 atoms of Na react?

5.

 

  1. 2Na(s) + 2H2O(ℓ) → 2NaOH(aq) + H2(g)
  2. 166 molecules

7.

For the balanced chemical equation

6H+(aq) + 2MnO4(aq) + 5H2O2(ℓ) → 2Mn2+(aq) + 5O2(g) + 8H2O(ℓ)
 

how many molecules of H2O are produced when 75 molecules of H2O2 react?

7.

120 molecules

9.

Given the balanced chemical equation

Fe2O3(s) + 3SO3(g) → Fe2(SO4)3
 

how many molecules of Fe2(SO4)3 are produced if 321 atoms of S are reacted?

9.

107 molecules 

11.

For the balanced chemical equation

Fe2O3(s) + 3SO3(g) → Fe2(SO4)3
 

suppose we need to make 145,000 molecules of Fe2(SO4)3. How many molecules of SO3 do we need?

11.

435,000 molecules

13.

Construct the three independent conversion factors possible for these two reactions:

  1. 2H2 + O2 → 2H2O
  2. H2 + O2 → H2O2
     

Why are the ratios between H2 and O2 different?

The conversion factors are different because the stoichiometries of the balanced chemical reactions are different.

13.

a.

2 molecules H 2 1 molecule O 2 , 1 molecule O 2 2 molecules H 2 O , 2 molecules H 2 2 molecules H 2 O

 

b.

1 molecule H 2 1 molecule O 2 , 1 molecule O 2 1 molecule H 2 O 2 , 1 molecule H 2 1 molecule H 2 O 2

Click here to return to Chapter 6